A ladder of length 29 feet is learning against the wall of the building and is such that the foot of the ladder is 21 feet from the base of the building. How far above the ground does the leader touch the buliding?
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It forms a triangle ABC,
Now,
AB (hypotenuse) = 29 ft
BC (base) = 21 ft
and AC is the height
using Pythagorean theorem, we have,
AB^2 = BC^2 + AC^2
=> AB^2 - BC^2 = AC^2
=> 29^2 - 20^2 = AC^2
=> 400 = AC^2
=> sqrt (400) = AC
Therfore AC = 20
Hence the leader touches the building by 20 ft above the ground
Now,
AB (hypotenuse) = 29 ft
BC (base) = 21 ft
and AC is the height
using Pythagorean theorem, we have,
AB^2 = BC^2 + AC^2
=> AB^2 - BC^2 = AC^2
=> 29^2 - 20^2 = AC^2
=> 400 = AC^2
=> sqrt (400) = AC
Therfore AC = 20
Hence the leader touches the building by 20 ft above the ground
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