Question

A ladder of length 5 m is placed against a 4 m long wall. Find the distance of the ladder from the foot of the wall

Answer 1

according to pythogorean theorm ,
hypotenuse ^2=Base^2+height^2
5^2=base^2+4^2
25=base^2+16
25-16=base ^2
9=base ^2
√9=base^2
3m = base

Answer 2

According to the problem given ,

Length of the ladder = AC = 5m

Height of the wall = BC = 4cm

Distance between foot of the ladder

to foot of the wall = AB

In ∆ABC , <B = 90°

By Phythogarian theorem ,

AC² = AB² + BC²

=> AC² - BC² = AB²

=> AB² = AC² - BC²

= 5² - 4²

= 25 - 16

AB² = 9

AB = √9

=> AB = 3 m

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