a ladder reaches a window which is 12 m above the ground on one side of street, keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 9 m high. find the width of the street if the length of the ladder is 15 m
nilanjanryon21p60n0p:
no one ??
its the other side of the buliding
just the opposite of that particular building where the laddar stays
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In △ABC△ABC
AB2+BC2122+BC2⟹BC=AC2=152=9mAB2+BC2=AC2122+BC2=152⟹BC=9m
In △DCE△DCE
DE2+CE292+CE2⟹CE2CE=DC2=152=225−81=12mDE2+CE2=DC292+CE2=152⟹CE2=225−81CE=12m
Hence the width of the street is BC + CE = 9+12 = 21m
AB2+BC2122+BC2⟹BC=AC2=152=9mAB2+BC2=AC2122+BC2=152⟹BC=9m
In △DCE△DCE
DE2+CE292+CE2⟹CE2CE=DC2=152=225−81=12mDE2+CE2=DC292+CE2=152⟹CE2=225−81CE=12m
Hence the width of the street is BC + CE = 9+12 = 21m
didnt got it
answer is ryt but didnt understood
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