A lady has only 20- paisa coins and 25 - paisa coins in her purse . If she has 50 coins in all totaling Rs 11.50 how many coins of each kind does she have
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Answered by
1
let the number of 20 paisa coins be x and 25 paisa coins be y
so , 20x +25y = 1150 (1) ( convering values in paisa)
and x +y = 50 (2)
so x = 50 - y
putting the value of x in equation (1)
so, 20(50 - y) + 25y = 1150
1000 - 20y + 25y = 1150
5y = 1150 -1000
5y = 150
y = 30
so the number of coins 25 paisa is 30 now putting this value of y in eq 2
x + y = 50
x + 30= 50
and y =20
so , 20x +25y = 1150 (1) ( convering values in paisa)
and x +y = 50 (2)
so x = 50 - y
putting the value of x in equation (1)
so, 20(50 - y) + 25y = 1150
1000 - 20y + 25y = 1150
5y = 1150 -1000
5y = 150
y = 30
so the number of coins 25 paisa is 30 now putting this value of y in eq 2
x + y = 50
x + 30= 50
and y =20
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0
hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝
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