Question

A lady has only 25 paise and 50 paise coin in her purse. if in all, she has 40 coin worth escorts 12.75, how many of each type does she have?

Answer 1

number of 50 paise coins =x

number of 25 paise coins=y

x+y=40---(1)

50x+25y=1275

divide each term with 25

2x+y=51----(2)

subtract (1) from (2)

x=11

substitute x=11 in (1) u get

y=29

therefore

number of 50paise coins=x=11

number of 25 paise coins=y=29

Answer 2

Heya!!

here's your answer!!!

let the number of 25 paise coins be x and the number of 50 paise coin be y.

it is given that total number of coin = 40

∴ x+y = 40

since the total amount = Rs 12.75 = 1275p
∴ 25x+50y = 1275

x+y = 51

subtracting (1) from (2), y = 11

putting in (1),

x+11 = 40

∴ x = 40-11=29

therefore the lady has 29 coins of 25 paise each and 11 coins of 50 paise each.

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