A lamp can work on a 50 volt mains taking 2 amps.What value of the resistance must be connected in series with it so that it can be operated from 200 volt mains giving the same power.
Answers
Answered by
174
V = 50 V
I = 2 A
V = IR
50 = 2(R)
R = 25 ohm
P = V^2/R = 2500/25 = 100 W
P = 40000/R'
R' = 400 ohm
R' = R + R"
400 = 25 + R"
R" = 375 ohm
I = 2 A
V = IR
50 = 2(R)
R = 25 ohm
P = V^2/R = 2500/25 = 100 W
P = 40000/R'
R' = 400 ohm
R' = R + R"
400 = 25 + R"
R" = 375 ohm
Answered by
50
Answer:
Explanation:
V = 50 V
I = 2 A
V = IR
50 = 2(R)
R = 25 ohm
P = V^2/R = 2500/25 = 100 W
P = 40000/R'
R' = 400 ohm
R' = R + R"
400 = 25 + R"
R" = 375 ohm
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