Physics, asked by jaspreet1bains, 6 months ago

A lamp consumes 5000J of electrical energy in 100 sec.what is its power ?​

Answers

Answered by Cosmique
2

Given :

  • Electrical energy consumed by Lamp, E = 5000 J
  • time taken, t = 100 sec

To find :

  • Power of Lamp, P = ?

Formula required :

  • Formula to calculate power

        P = E / t

[ Where P is power, E is energy, t is time ]

  • Electrical power is defined as the electrical energy consumed per unit time.
  • SI unit of Electrical power : Watt
  • 1 Watt = 1 Joule/sec
  • Dimensional formula : [ M L² T⁻³ ]

Calculation :

Using formula for Electrical power

→ P = E / t

Putting values in RHS

→ P = 5000 / 100

P = 50 Watt

Therefore,

  • Power of Lamp is 50 Watt.
Answered by Rudranil420
4

Answer:

Given

A lamp consumes 5000J of electrical energy.

Time= 100 sec

To Find

Power = ?

Formula Used

P = \dfrac{E}{t}

( where,

  • P = power
  • E = energy
  • t = Time taken

Solution

According to the question by using formula we get,

=> P = \dfrac{5000}{100}

=> P = \text{\large\underline{\pink{50 watt}}}

Power of lamp is 50 watt.

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