A lamp of resistance 20 Ω and a conductor of resistance 8 Ω are
connected with a battery of 8 V in series. Calculate the :
(a) total resistance in the circuit
(b) current flowing through the circuit
Answers
Answered by
4
total resistance...
since they are connected in series R = R1+R2
R= 20 +8 =28
Total current flowing in the circuit
= V = I REALLY
8 = I × 28
8/28= I
FIND THE current ....that's the answer
HOPE THIS HELPS YOU FRIEND. ..
Dev0000:
2nd part ko age to solve krr
Answered by
3
1.total resistance is 28 ohm
2.total current is 4/14 ampere
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