A lamp wich is connected to 230v draws a current of 0.261A calculate the power and hot resistence of the lamp?
Answers
Answered by
129
Answer:
- Power of Lamp is 60 Watt.
- Resistance of lamp is 881.22 Ohms
Explanation:
Given:-
- Potential Difference ,P = 230 v
- Current ,I = 0.261 A
To Find:-
- Power of Lamp ,P
- Resistance ,R
Solution:-
Firstly we calculate the Resistance of the Lamp.
Using Ohm's Law
• V = IR
where,
- V denote Potential Difference
- I denote Current
- R denote Resistance
Substitute the value we get
→ 230 = 0.261 × R
→ R = 230/0.261
→ R = 230000/261
→ R = 881. 22Ω
- Hence, the Resistance of the Lamp is 881.22 ohms.
Now, calculating the Power
• P = V²/R
Substitute the value we get
→ P = 230²/881.22
→ P = 230×230/881.22
→ P = 52900/881.22
→ P = 60.03 ≈ 60 W
- Hence, the Power of the Lamp is 60 Watt.
deepthisirikonda:
tq u
Answered by
141
QuestioN :-
⠀⠀
- A lamp which is connected to 230v draws a current of 0.261A. Calculate the power and hot resistance of the lamp.
⠀
Given :-
A lamp is connected to 230v draws a current of 0.261A
So,
- the Potential Difference (P) = 230v
- Current (i) = 0.261 A
To FinD :-
- The power of lamp
- Hot resistance (r)
⠀
AnsweR :-
First , Let's find out the Resistance of the lamp :-
we know that :-
- V = ir ( Ohm's law )
Where ,
Putting the values we have into the ohm's law :-
Now , to FinD the the Power :-
Using the identity -
Hence , the Resistance = 881.22 ohm's and power = 60.03 w.
_____________________________
Hope it will help you :)
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