Question

A land is in the shape of rhombus the perimeter of the land is 160m and one of the diagonal is 48m find the area of the land

Answer 1

Answer:1536

Step-by-step explanation:

Perimeter=4*side

So side =160/4=40

Area of rhombus=product of length of diagonals/2

In the figure AD=48

So AO=24

In right angle triangle AOB

By hypotenuse theorem

40*40=24*24-(BO)^2

So 1600-576=BO^2=1024

BO=32

BC=64

Area =64*48/2=3072/2=1536