A land is in the shape of rhombus.The perimeter of the land is 160m and one of the diagonal is 42m.Find the area of parallelogram.
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Answer:
1430 m²
Step-by-step explanation:
Perimeter of the land = 160 m.
=> 4a = 160
=> a = 40 m
Given,
One of the diagonal = 42 m
∴ Area of land = 2 * Area of ΔBC
s = (40 + 40 + 42)/2
= 61 m
Area of ΔABC = √s(s - a)(s - b)(s - c)
= √61(61 - 40)(61 - 40)(61 - 42)
= √511119
= 715 m²
∴ Area of parallelogram = 2 * 715
= 1430 m²
Hope it helps!
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Answer:
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