Math, asked by dkrohith006, 11 months ago

A land is in the shape of rhombus.The perimeter of the land is 160m and one of the diagonal is 42m.Find the area of parallelogram.​

Answers

Answered by Siddharta7
0

Answer:

1430 m²

Step-by-step explanation:

Perimeter of the land = 160 m.

=> 4a = 160

=> a = 40 m

Given,

One of the diagonal = 42 m

∴ Area of land = 2 * Area of ΔBC

s = (40 + 40 + 42)/2

 = 61 m

Area of ΔABC = √s(s - a)(s - b)(s - c)

                       = √61(61 - 40)(61 - 40)(61 - 42)

                       = √511119

                       = 715 m²

∴ Area of parallelogram = 2 * 715

                                         = 1430 m²

Hope it helps!

Answered by Bhawnasrivastava89
0

Answer:

plz mark as brainlist answer....

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