Question

A lane 150 m long and 9 m wide is to be paved with bricks, each measuring 25 cm by 75 cm.
How many bricks are required?

Answer 1

Answer:

80000 bricks are required.

Step-by-step explanation:

Given 

Length of the road =150 m

=15000 cm

Breadth of the road =9 m

=900 cm

Area of the road = (length \times breadth)

=(15000×900)

=13500000 cm2

Given length of the brick =22.5 cm

Breadth of the brick =7.5 cm

Area of the brick =(length × breadth)

=(22.5×7.5)

=168.75 cm2

Number of bricks = Area of the road/ Area of one brick

=13500000/168.75

Number of bricks =80000 bricks

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Answer 2

Answer : There will be 7200 bricks required for the pavement of lane.

Given a lane 150 m long and 9 m wide is to be paved with bricks, each measuring 25cm by 75 cm. The number of bricks is to be found.

Finding the area of the lane,

Area of Rectangle = length × breadth

Area of the lane = 150 × 9

Area of the lane = 1350 m²

Now, finding the area of the brick,

changing the dimensions of brick,

length be, 75 cm = 0.75 m

breadth be, 25 cm = 0.25 m

Area of the brick = 0.75 × 0.25

Area of the brick = 0.1875 m²

Now, to get the number of bricks

dividing the area of lane by the area of the brick

Number of bricks = Area of the lane / Area of the brick

Number of bricks = 1350 / 0.1875

Number of bricks = 7200

So, to conclude in a single sentence there will be 7200 bricks required for the pavement of lane.

Learn more about Areas by clicking the link below,

https://brainly.in/question/818497

Learn more about Unitary Method by clicking the link below,

https://brainly.in/question/861311

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