Verify Rolles theorem for f(x) = x3 2x2 - 8x on [-2,4].
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Step-by-step explanation:
f(x)=x
2
+2x−8
⇒f(x)=(x+4)(x−2)
f
′
(x)=2x+2
We know every polynomial function is continuous and differentiable in R.
In particular f is continuous and differentiable in [−4,2]
Also f(−4)=f(2)=0
Thus there will exist c∈(−4,2) such that f
′
(c)=0
⇒2c+2=0⇒c=−1∈(−4,2)
Hence, Rolle's theorem verified.
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