a lane 180m long and 5m wide is to be paved with bricks, of length 20cm and breadth 15cm find the cost of brick that are required, at the rate of rupee 750 per thousand.
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For a lane
Length =180m
=(180 * 100) cm (1m=100cm)
=18000 cm
Breadth = 5m
=(5 * 100) cm (1m=100cm)
=500 cm
Area= L * B
= 18000 * 500
= 9000000 cm(Square)
For a brick
Length =20cm
Breadth =15cm
Area = L * B
=20 * 15
=300cm(Square)
Number of bricks required = Area of lane/ Area of a Brick
=9000000/300
=30000
Cost of 1 thousand bricks = Rupees 750
Cost of 30 thousand bricks = Rupees 750 * 30 Thousand
= Rupees 22500
Hence, Cost of paving the lane= Rupees 2,25,000
Length =180m
=(180 * 100) cm (1m=100cm)
=18000 cm
Breadth = 5m
=(5 * 100) cm (1m=100cm)
=500 cm
Area= L * B
= 18000 * 500
= 9000000 cm(Square)
For a brick
Length =20cm
Breadth =15cm
Area = L * B
=20 * 15
=300cm(Square)
Number of bricks required = Area of lane/ Area of a Brick
=9000000/300
=30000
Cost of 1 thousand bricks = Rupees 750
Cost of 30 thousand bricks = Rupees 750 * 30 Thousand
= Rupees 22500
Hence, Cost of paving the lane= Rupees 2,25,000
Janni1:
tqs
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