Math, asked by causeylatasha88, 5 months ago

A large bagel spins with angular speed W about its center. a smaller bagel spins with triple the angular speed
how does the period Large of the large bagel compare with period T small of the small bagel?

Answers

Answered by amitnrw
2

Given : A large bagel spins with angular speed ω about its center. a smaller bagel spins with triple the angular speed

To Find : how does the period of the large bagel compare with period T small of the small bagel?

Solution:

angular velocity ω is the angle covered divided by the time taken  

time rate of angle covered.

The time period T is the time taken to repeat the motion

ω = Δθ / Δt

=> ωΔt =  Δθ

A large bagel spins with angular speed  ω

a smaller bagel spins with triple the angular speed = 3ω

Δθ = 360°  (2π)  for Time period T

ωT₁ =  2π

3ωT₂ =   2π

=>  ωT₁ = 3ωT₂

=> T₁  = 3 T₂

Time period of   large bagel will be 3 times the Time period of  small  bagel

Learn More:

at a certain place, the length of a seconds pendulum is 100cm. find ...

https://brainly.in/question/10592449

the median time for the period 1 february to 20 september of leap ...

https://brainly.in/question/26797934

Similar questions