A large bagel spins with angular speed W about its center. a smaller bagel spins with triple the angular speed
how does the period Large of the large bagel compare with period T small of the small bagel?
Answers
Given : A large bagel spins with angular speed ω about its center. a smaller bagel spins with triple the angular speed
To Find : how does the period of the large bagel compare with period T small of the small bagel?
Solution:
angular velocity ω is the angle covered divided by the time taken
time rate of angle covered.
The time period T is the time taken to repeat the motion
ω = Δθ / Δt
=> ωΔt = Δθ
A large bagel spins with angular speed ω
a smaller bagel spins with triple the angular speed = 3ω
Δθ = 360° (2π) for Time period T
ωT₁ = 2π
3ωT₂ = 2π
=> ωT₁ = 3ωT₂
=> T₁ = 3 T₂
Time period of large bagel will be 3 times the Time period of small bagel
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