Question

A large ball 2 m in radius is made up of a
rope of square cross section with edge
length 4 mm. Neglecting the air gaps in
the ball, what is the total length of the
rope to the nearest order of magnitude?​

Answer 1

Answer:

4/3 x π x r ^3 = (a X a) X L

L = (4/3 x π x r ^3) / ( a X a)

L= (4 x 22 x 2 x 2 x 2) / [(0.004 X 0.004) x (3 x 7)]

= 2095238 m