A large concave mirror has a radius of curvature of 1.5 m. A person stand 10 m in front of the mirror. Where is the person's image?
Answers
Answered by
334
Radius of Curvature (R) = - 1.5 m(concave mirror)
Object distance (u) = -10 m [Object distance is negative in Concave mirror]
Image distance (v) = ?
f = R/2
Focal length (f) = -1.5/2 = - 0.75 m
Mirror Formula
1/v + 1/u = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(-10)
1/v = 1/0.75 + 1/10
1/v= - 100/75 +1/10
1/v = -4/3+ 1/10
1/v= (-4×10+3)/30
1/v= (-40+3)/30
1/v = -37/30
v= -30/37
v = - 0.81 m
Hence,the person's will be 0.81 m infront of the concave mirror.
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Hope this will help you....
Object distance (u) = -10 m [Object distance is negative in Concave mirror]
Image distance (v) = ?
f = R/2
Focal length (f) = -1.5/2 = - 0.75 m
Mirror Formula
1/v + 1/u = 1/f
1/v = 1/f - 1/u
1/v = 1/(-0.75) - 1/(-10)
1/v = 1/0.75 + 1/10
1/v= - 100/75 +1/10
1/v = -4/3+ 1/10
1/v= (-4×10+3)/30
1/v= (-40+3)/30
1/v = -37/30
v= -30/37
v = - 0.81 m
Hence,the person's will be 0.81 m infront of the concave mirror.
==================================================================
Hope this will help you....
Answered by
104
HEYA MATE!!!!
Here is your answer
r = 1.5cm
u = -10cm
v =?
f = r/2 = -1.5/2 = 0.75
We know,
By mirror formula,
1/v + 1/u = 1/f
1/v + 1/-10 = 1/-0.75
1/v - 1/10 = 1/-0.75
1/v - 1/10 = -100/75
1/v = -100/75 + 1/10
1/v = -4/3 + 1/10
1/v = (-40 + 30)/ 30
1/v = -37/30
V = 30/ 37
V = 0.81
So, 0.81m in front of concave mirror
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I hope it will helpful to you…
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