Chemistry, asked by shravya7206, 1 year ago

A large conducting plane has a surface charge density 1·0×10-4 C m-2. Find the electrostatic energy stored in a cubical volume of edge 1⋅0 cm in front of the plane.

Answers

Answered by papiyamondal80
0

Answer:

Sorry I can't answer to your question

Answered by shilpa85475
3

The electrostatic energy stored in a cubical volume of edge 1⋅0 cm in front of the plane is equal to the 5.65 X 10^{-4} J

Explanation:

Given,

The surface density of the plane,

\sigma=1.0 \times 10^{-4} \frac{C}{m^{2}}

Volume of the cube,

V=a^{3}=10^{-6} \mathrm{m}^{3}

Electric field near the charged conducting plane is given by

E=\frac{\sigma}{\epsilon_{0}}                      

Energy Density of the Electric field,

u=\frac{1}{2} \in_{0} E^{2}

u=\frac{1}{2} \in_{0}\left(\frac{\sigma}{\epsilon_{0}}\right)^{2}

u=\frac{1}{2} \frac{\sigma^{2}}{\epsilon_{0}}

u=\frac{1}{2} \times \frac{\left(1.0 \times 10^{-4}\right)^{2}}{8.85 \times 10^{-12}}

u=0.056 \times 10^{4} \frac{j}{m^{3}}

Volume =  10^{-6} \mathrm{m}^{3}

U=u \times V

U=0.056 \times 10^{4} \times 10^{-6}

U=5.6 \times 10^{-4} J

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