Question

A large plane sheet of charge having a surface charge density of 5 x 10-6 C/m2 lies in xy-plane.Find the electric flux through a circular area of radius 0.1 m if the normal to the circular area makes an angle of 60o with the z-axis.

Answer 1

surface charge density on large plane sheet is $\sigma=5\times10^{-6}C/m^2$

so, electric field due to plane sheet, E= $\frac{\sigma}{2\epsilon_0}$

= 5 × 10^-6/(2×8.85× 10^-12)

= (5/17.7) × 10^6 N/C

area of circular plane sheet , A = πr²

= π(0.1m)² = 0.01π m²

a/c to question,

the normal to the circular area makes an angle of 60° with the z-axis.

means, angle between electric field and area vector is 60°

so, electric flux through circular sheet = E.Acos60°

= (5/17.7) × 10^6 × 0.01π × 1/2N/C

= 4.44kV

Answer 2

Answer:

here's the answer of this question

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