Physics, asked by elakyaarjun, 10 months ago

A large solid sphere of diameter d attracts a small particle with a force FF. If the central portion of the sphere of diameter d2d2 be removed leaving behind a cavity, then the new force of attraction becomes​

Answers

Answered by aristocles
6

Answer:

the new force of attraction becomes 7/8 times of initial force

Explanation:

As we know that the gravitational force of attraction between two masses is given by

F = \frac{GmM}{r^2}

here one of the particle is a sphere of diameter "d"

so we will have

M = \rho (\frac{4}{3} \pi R^3)

now when central part of the sphere of diameter d/2 is removed then the remaining mass of the sphere is given as

M_{remain} = \rho(\frac{4}{3}\pi (R^3 - (\frac{R}{2})^3)

M_{remain} = \frac{7}{8}\rho (\frac{4}{3}\pi R^3)

so we will have

M_{remain} = \frac{7}{8}M

so new force of attraction between the two masses is given as

F' = \frac{G(7M/8)m}{r^2}

so the new force of attraction becomes 7/8 times of initial force

#Learn

Topic : Gravitational Force

https://brainly.in/question/6648726

Similar questions