A large water - melon weighs 20 kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that only 95% of its weight is water. Its reduced weight will be ?
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20kg watermelon
It is allowed to stand in the sun and some of the water evaporates so that only 95% of its weight is water. Its reduced -weight will be 16 kg b.
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Answer:
Weight of water in the 20 kg water - melon
= 96 × 20/100 = 19.2 kg
Weight of water - melon pulp = 20 kg - 19.2 kg
= 0.8 kg
Let the reduced weight of the water - melon after evaporation = 95%
Weight of water in the water - melon after evaporation = 95 %
☞ Weight of pulp = 5%
Therefore 5% of x = 0.8 kg
☞ x = 0.8 kg × 100/5 = 16 kg.
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