Question

A large water melon weighs 20 kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. Its reduced will be ​

Answer 1

In 20kg 96% is water I.e 19.2 kg and rest is non water part that is 0.8 kg.
Now it dries
So water is 95% that just mean non water part is 5% and non water cant be evaporate so it remains same I.e 0.8kg

5% ---> 0.8 kg
100% --> ?
= 16 kg answer
I hope it helps you bro

Answer 2

Answer:

Weight of water in the 20 kg water - melon

= 96×20/100 = 19.2 kg

Weight of water - melon pulp = 20 kg – 19.2 kg

= 0.8 kg

Let the reduced weight of the water - melon be x kg. Then,

Weight of water in the water - melon after evaporation = 95%

=> Weight of pulp = 5%

Therefore, 5% of x = 0.8 kg

=> 5% of x = 0.8 kg

=> x = 16 kg.