Question

A large water melon weighs 20 kg with 96% of its weight being water. It is allowed to stand in the sun and some of the water evaporates so that now only 95% of its weight is water. Its reduced will be ​

Answer 1

Answer:

Hey there!

Here is your answer.

Weight of water in the 20 kg water - melon

= 96×20/100 = 19.2 kg

Weight of water - melon pulp = 20 kg – 19.2 kg

= 0.8 kg

Let the reduced weight of the water - melon be x kg. Then,

Weight of water in the water - melon after evaporation = 95%

=> Weight of pulp = 5%

Therefore, 5% of x = 0.8 kg

=> 5% of x = 0.8 kg

=> x = 16 kg.

Answer 2

Answer:

Step-by-step explanation:

non water part wt (x) + water wt (96%) = 20 kg

x + 96/100 * 20 = 20 ————— 1

x + 19.2= 20

x = 0.8

non water part wt (x) + water wt (95%) = y kg (wt after dry)

x + 95/100 * y = y ——————-2

0.8 + 0.95 y = y

multiply by 100

80 + 95 y = 100 y

80 = 5 y

80 / 5 = y

Ans : y =16 kg

plz mark me the brainliest