Question

A laser emits a beam of light of 2mm diameter. If the power of beam is 10mW, the intensity of the beam of light is

Answer 1

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Solution _____

Area of the beam =A=π(diameter)24=A=π(diameter)24

=3.14×4×10−64=3.14×4×10−64=3.14×10−6m2=3.14×10−6m2

Intensity = PowerAPowerA

=10×10−33.14×10−6=10×10−33.14×10−6

=3184.713W/m2=3.18×103W/m2=3184.

713W/m2

=

3.18×103W/m2