Question

A lawn 30 m long and 16 m wide is surrounded by a path 2 m wide. find the area of the path.

Answer 1

Ello ❤❤

Here is your solution !

PQRS represents the rectangle lawn, and ABCD represents the outer edge of the lawn.

since PQ = 30 m, and since the path is 2 m wide.

AB = (30+2+2) m = 34 m

And
AD = (16+2+2) m = 20 m

therefore,

Area of ABCD = (34×20) m^2

and

Area of PQRS = (30×16) m^2

= 480 m^2

therefore

area of the path = area ABCD - area PQRS

= (680 - 480) m^2

= 200 m^2

Thanks dear !

Answer 2

Question:-

if a lawn 30m long 16 m wide is surrounded by a path 2m wide, what is the area of the path

solution:-

Let, L be the length of rectangle and B be the breadth rectangle.

By Question:-

We know formula of

=> Area of rectangle = L × B

=> Area of rectangle = 30 × 16

=> Area of rectangle = 480 m²

=> X = 480 m²

we know that length and breadth increase by 2 m from their both ends.

so,

=> L = 30 + 2 + 2 = 34 m.

=> B = 16 + 2 + 2 = 20 m.

We know formula of

=> Area of rectangle + path = L × B

=> Area of rectangle + path

= 34 × 20

=> Area of rectangle + path

= 680 m²

=> Z = 680 m²

=> Area of path =( Z ) - ( X )

=> Area of path = 680 - 480

=> Area of path = 200 m²

Area of path 200 m².

i hope it helps you.