Math, asked by alistajdav777777, 6 months ago

A lawn 30 m long and 16 m wide is surrounded by the path 2 m wide. Find the area of the path.

Answers

Answered by Anonymous
10

Answer:

200 m²

Step-by-step explanation:

Length of lawn + path(on both sides) = 30+2+2=34 m

Breadth of lawn + path(on both sides) = 16+2+2=20 m

∴Area of (lawn+path) = 34 × 20 = 680 m^{2}

 Area of lawn(without path) = 30 × 16 = 480 m^{2}

So, area of path = Area of (lawn+path) - Area of lawn(without path)

= 680 - 480 = 200 m²

Answered by nilesh102
32

Question:-

if a lawn 30m long 16 m wide is surrounded by a path 2m wide, what is the area of the path

solution:-

Let, L be the length of rectangle and B be the breadth rectangle.

By Question:-

We know formula of

=> Area of rectangle = L × B

=> Area of rectangle = 30 × 16

=> Area of rectangle = 480 m²

=> X = 480

we know that length and breadth increase by 2 m from their both ends.

so,

=> L = 30 + 2 + 2 = 34 m.

=> B = 16 + 2 + 2 = 20 m.

We know formula of

=> Area of rectangle + path = L × B

=> Area of rectangle + path

= 34 × 20

=> Area of rectangle + path

= 680 m²

=> Z = 680

=> Area of path =( Z ) - ( X )

=> Area of path = 680 - 480

=> Area of path = 200 m²

Area of path 200 m².

i hope it helps you.

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