If cos 0 + sin 0 = √2 cos 0, show that cos 0
- sin 0 = √2 sin 0.
(CBSE 2013]
Attachments:
Answers
Answered by
56
Answer:
I hope this will help you
Attachments:
advnuy:
thanks for your help
Answered by
34
Cosθ - Sinθ = √2 Sinθ if Cosθ + Sinθ = √2 Cosθ
Step-by-step explanation:
Cosθ + Sinθ = √2 Cosθ
Squaring both sides
=> Cos²θ + Sin²θ + 2CosθSinθ = 2Cos²θ
=> 2CosθSinθ = Cos²θ - Sin²θ
Cos² + Sin²θ = 1
Subtracting 2CosθSinθ from both sides
=> Cos² + Sin²θ - 2CosθSinθ = 1 - 2CosθSinθ
=> (Cosθ - Sinθ)² = 1 - 2CosθSinθ
using 2CosθSinθ = Cos²θ - Sin²θ
=> (Cosθ - Sinθ)² = 1 - (Cos²θ - Sin²θ)
=> (Cosθ - Sinθ)² = 1 - Cos²θ + Sin²θ
=> (Cosθ - Sinθ)² = Sin²θ + Sin²θ
=> (Cosθ - Sinθ)² = 2Sin²θ
=> Cosθ - Sinθ = √2 Sinθ
QED
Proved
learn more:
1/secx-tanx -1/cos = 1/cosx - 1/secx+tanx
https://brainly.in/question/8160834
sinx + cosx
https://brainly.in/question/3876174
Similar questions
Social Sciences,
6 months ago
Environmental Sciences,
6 months ago
Science,
6 months ago
Hindi,
11 months ago
Physics,
1 year ago