A lawn fertilizer recipe uses ammonium sulphate, iron sulphate and sharp sand in the ratio 3 : 1 : 20. 100 grams of fertilizer are needed for each square meter of lawn.
a) How much ammonium sulfate is needed to make 100 g of fertilizer?
b) Dave's lawn is a rectangle, 4 m long and 9 m wide. How much sharp sand does he need to fertilize his lawn?
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Ammonium Sulphate : Iron Sulphate : Sharp Sand
→ 3 : 1: 20
Ammonium Sulphate = 3x
Iron Sulphate = 1x
Sharp Sand = 20x
Total quantity = 100 gm
3x + 1x + 20x = 100
24x = 100
x = 100/24
= 4.16 gm
a) Quantity of Ammonium sulphate = 3(4.16) gm
= 12.48 gm
b) Quantity of Sharp Sand/ 100 gm = 20(4.16)
= 83.2 gm
Area of lawn = 4(9) m²
= 36 m²
Quantity of Sharp Sand = 36(83.2) gm
= 2995.2 gm
→ 3 : 1: 20
Ammonium Sulphate = 3x
Iron Sulphate = 1x
Sharp Sand = 20x
Total quantity = 100 gm
3x + 1x + 20x = 100
24x = 100
x = 100/24
= 4.16 gm
a) Quantity of Ammonium sulphate = 3(4.16) gm
= 12.48 gm
b) Quantity of Sharp Sand/ 100 gm = 20(4.16)
= 83.2 gm
Area of lawn = 4(9) m²
= 36 m²
Quantity of Sharp Sand = 36(83.2) gm
= 2995.2 gm
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