a lead ball of mass 2kg fall from a height of 30.0m .if the total kinetic energy of the ball is converted into heat and remains in it, calculate rise in temperature of the ball when it strikes the ground. find the change into internal energy of the ball in this process . solve this numerical only
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Answer:
u=mgh 2×9.8×30=588j
Explanation:
cpdt =588, dt =588/2×125=2.35 specific heat 125×2
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