Let triangle ABC ~triangle DEF&their areas be, respectively, 64cmsquare & 121cm square. If EF=15.4cm, find BC
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we know that if two triangles are similar then
ar(ABC)/ar(DEF)=
![bc ^{2} \div ef ^{2} bc ^{2} \div ef ^{2}](https://tex.z-dn.net/?f=bc+%5E%7B2%7D++%5Cdiv+ef+%5E%7B2%7D+)
》64/121=(bc)sq/(15.4)sq
8/11=bc/15.4
bc=(15.4×8)/11=1.4×8=11.2cm
Hope it helps!
ar(ABC)/ar(DEF)=
》64/121=(bc)sq/(15.4)sq
8/11=bc/15.4
bc=(15.4×8)/11=1.4×8=11.2cm
Hope it helps!
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