a leader rests on a pole such that the base of the letter is 27 DM away from the base of the pole top of the letters the top of the ball at a height of 20m complete the following activity to find the length of the leader
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Step-by-step explanation:
In ΔABC
∠ABC = 90°
∴ By Pythagoras Theorem,
AC² = AB² + BC²
∴AC² = 120² + 27²
= 14400 + 729
= 15129
∴AC = √15129
∴AC = 123
Length of the ladder is 123 dm
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u answered to my question but it has been deleted
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