Question

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, wle Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day.

Answer 1

let x = fixed charge for three days
let y = additional charge
A.T.Q

x +4y=27.......(1)

x +2y =21.......(2)

multiply equation (2) with 2.....we get

2x +4y = 42......(3)


by elimination method solve (1) and
(3) equation we get ..

x= 15 then y= 12

Answer 2

Answer:

Let the fixed charge for first three days and each days charge be Rs x and Rs y respectively.

$\large{\underline{\mathfrak{\pink{According\:\:to\:\:the\:\:given\:\:information\:\::-}}}}$

$\\ \boxed{ \sf{\orange{x + 4y = 27}}} \: \: \: \: \: \: \: - - - - - \: \: \: \: \: (1) \\ \\ \\ \boxed{ \sf{ \green{x + 2y = 21}}} \: \: \: \: \: \: \: - - - - - \: \: \: \: \: (2)$

Subtracting equation (1) from equation (2), we obtain :

$\\ \sf \: 2y = 6 \\ \\ \\ \sf \blue{y = 3}$

Substituting it in equation (1), we obtain :

x+12 = 27

=> x = 15

• Fixed charge = 15
• charge per day = 3