Math, asked by reenagrg669, 1 month ago

A lending library has a fixed charge for the first three days and an additional charge for each day thereafter,Sarita paid RS. 27 for a book kept for 7 days while Sussy paid RS. 21 for the book she kept for 5 days . Find the fixed charge and the charge for each extra day .


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Answers

Answered by Anonymous
1

Let the fixed charge for 3 days = x and

additional charge = y

According to the question

⇒ x + 4y = 27....eq1

⇒ x + 2y = 21....eq2

Subtract eq1 and eq2

⇒ (3x + 4y = 27) − (3x + 2y = 21) ⇒ 2y =

6 ⇒ y = 3 put y = 3 in eq1

→ X+4× 3 = 27 x = 15

Fixed charges = Rs. 15

The charge for each extra day = Rs. 3

Answered by nitishkhokhar6
1

Answer:

Let the fixed charge be Rs. x

and the extra charge be Rs. y

x+4y=27⟶(i)

x+2y=21⟶(ii)

On substracting (i) and (ii),

2y=6

y=3

putting y in (i),

x+4(3)=27

x=15

∴x=Rs.15 and y=Rs. 3

∴ Fixed charge =Rs. 15

∴ Charge for each extra day =Rs. 3 .

Step-by-step explanation:

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