A length of 63 meters long is divided into two parts in the same way when the length of a part is the fifth part of the second part, the length of the small piece?
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Heya !
Here's your answer !!
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GIVEN THAT :
Length = 63 m
ON DIVIDING :
Length of the first part is one fifth of the second part. Hence, the first part is smaller than the second part.
TO FIND :
Length of the small piece.
SOLUTION :
Let the length of second part be x
First part = 1/5 × x
A.T.Q.
=> x + x/5 = 63
=> ( 5x + x )/5 = 63
=> 6x/5 = 63
=> x = 63 × 5/6
=> x = 21 × 5/2
=> x = 21 × 2.5
=> x = 52.5 m
Length of small part =
=> 52.5/5
=> 10.5 m ANS
___________________________
THANKS !!
Here's your answer !!
________________________
GIVEN THAT :
Length = 63 m
ON DIVIDING :
Length of the first part is one fifth of the second part. Hence, the first part is smaller than the second part.
TO FIND :
Length of the small piece.
SOLUTION :
Let the length of second part be x
First part = 1/5 × x
A.T.Q.
=> x + x/5 = 63
=> ( 5x + x )/5 = 63
=> 6x/5 = 63
=> x = 63 × 5/6
=> x = 21 × 5/2
=> x = 21 × 2.5
=> x = 52.5 m
Length of small part =
=> 52.5/5
=> 10.5 m ANS
___________________________
THANKS !!
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