Question

A length of rope is placed on the floor in the shape of an equilateral triangle of side 2.2 m. If this rope is spread out and a circle is formed out of it, what will be the radius of the circle?ans-1.05m.
Pls solve

Answer 1

Solution :-

Rope is placed in the form of equilateral triangle

Length of the side of the equilateral triangle (a) = 2.2 m

We know that

Perimeter of the equilateral triangle = 3a

= 3(2.2)

= 6.6 m

Same rope is spread out in the form of a circle

Let the radius of the circle be r

We know that

Perimeter of the circle = 2πr

= 2 * 22/7 * r

= 44r/7

According to the question

Perimeter of the circle = Perimeter of the equilateral triangle

⇒ 44r/7 = 6.6

⇒ 44r = 6.6 * 7

⇒ 44r = 46.2

⇒ r = 46.2/44

⇒ r = 462/440

⇒ r = 1.05 m

Therefore the radius of the circle is 1.05 m.

Answer 2

Answer:

Step-by-step explanation:

Perimeter of the equilateral

Triangle = 2.2*3 m

=6.6 m

As the length of the rope is 6.6m

The circumference of circle=6.6m

Let radius be r

2*22/7* r =6.6

or r=06.6*7/(44)

or r = 1.05m