Question

a length of rope is placed on the floor in the shape of an equilateral triangle of side 2.2 metre . if this rope is spread out and the circle is formed out of it, what will be the radius of the circle

Answer 1

the perimeter of the triangle is =3*2.2=6.6m
if circle is formed by this rope so the circumference of circle is equal to perimeter of triangle
therefore, radius=6.6/2Π=6.6/6.28=1.05m is the radius of circle

Answer 2

Hiii......

Perimeter of triangle = perimeter of circle

$= > \: \: \: 3 \times 2.2 = 2\pi \times r$
=> 6.6 = 2 × 22/ 7 × r

So,


r = 6.6 × 7/ 22

Therefore,

r = 2.1 cm........ANS

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