Question

A lens formed image of an object twice of its size having focal length 15cm find the position of the

Answer 1

ANSWER

f=−15cm

m=+2(positionbecauseimagevirtual)

m=− u/v

⇒v=−2u

byusingmirrorformula

−1/15 = 1/(−2u) + 1/u

⇒u=−7.5cm

positionofobjectis7.5cm