a lens place at a distance of 20 cm from an object produces virtual image of 2/3 the size of the object Find the position of image kind of lens and focal length.
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u=-20. m=2/3
v=? lens=? f=?
m=v/u
2/3=v/-20
-40/3=v
-13.3=v
f=1/v-1/u
=3/-40-1/-20
=-1/40
f=-40
lens= concave lens
hope it will help you
v=? lens=? f=?
m=v/u
2/3=v/-20
-40/3=v
-13.3=v
f=1/v-1/u
=3/-40-1/-20
=-1/40
f=-40
lens= concave lens
hope it will help you
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