Question

A letter A is constructed of a uniform wire of res stance 1 Ohm per cm.
The sides of the letter are each 20 cm long and the cross piece in middle
us 10 cm long. Find the resistance of the letter between the ends of its
(02)
two legs.
catalanomnosition and nhotochemical de​

Answer 1

Explanation:

Here is the answer to your question

Since the angle of the apex is 60, that means the other two angles are also 60 and this is an equilateral triangle. That means the length from the apex to the cross side is the same as the cross side = 10cm which is 1ohm/cm * 10cm = 10 ohm. Thus the other wire from the apex to the other side of the cross side is also 10 ohm. Thus the wire in parallel with the cross side is 10+10 = 20 ohms.

The cross side is 10cm * 1 ohm/cm = 10 ohm

10 ohms in parallel with 20 ohms: 10||20 = 200/30 = 20/3 ohms.

The resistance of each leg to the cross side is then 10cm * 1 ohm/cm = 10 ohms. So the total resistance seen from the legs is 10 + 20/3 + 10 = 80/3 ohms = 26 and 2/3 ohms = 26.67 ohm