Question

A letter is chosen at random from the alphabet .Find the probability that it is
1.A or B
2.one of the letter of the word "Random"
3.one of the letters of the word "Choice"

Answer 1

Answer:

Total number of letters=26

1. Total number of probabilities=2

E(AorB)= 2/26=1/13

2. Total number of probabilities=6

E(one of the letters from RANDOM)=6/26=3/13

3. Total number of probabilities=5

E(one of the letters from CHOICE)=5/26

Answer 2

Answer:

Probability of the letter A =outcomes favourable to A /total outcomes

= 1/26

like wise probability of B is 1/26

2) probability of letter of word random = outcomes favourable to the event / total outcomes

= 6/26

= 3/13

3) probability of letter of word choice. 6/26

=3/13