Math, asked by nik0606, 1 year ago

A letter is chosen at random from the letters of the word 'ASSASSINATION'. Find the probability that the letter chosen is vowels,consonant.

Answers

Answered by Anonymous
9

P(E) = No. Of outcome / Total No. Of outcome

"ASSASSINATION" it contains 13 letters

1. Total No. Of outcome is 13

There are 6 vowels in these letter

P(E) = 6/13

2. Total No. Of outcome is 13

There are 7 consonants in these letter

P(E) = 7/13

Answered by Arcel
18

Answer:

(i) 6 / 13

(ii) 7 / 13

Step-by-step explanation:

Given:

An experiment consists of a letter chosen at random from the word ‘ASSASSINATION’ which consists 13 letters,

(6 vowels and 7 consonants)

∴ Sample points are 13.

Solving:

(i) Let E be the event that chosen letter is a vowel

E = {A, A, A, I, I, O}

∴ n(E) = 6

P(E) = n(E) / n(S) = 6 / 13

(ii) Let E be the event that chosen letter is a consonant

∴ F = {S, S, S, S, N, N, T}

P(F) = n(F) / n(S) = 7 / 13

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