A lever of length of 100cm has efforts of 15 kgf at distance of 40 CM from the fulcrum at one end what load can be applied at another end and write formula
mdzunaid:
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the formula is Torque = force x distance x is a cross product.
here, torque has to be balanced,so => 15 x 40 = 60 x (required force).so required force = 10kgf
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