Question

A lift in a mine moves down 24m in 87 mines if it moves in uniform rate, find at what distance below the surface, it will be after 6 mins. if the lift starts from a height 10 m above the ground find how deep the lift will go from the surface after 70 mins











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Answer 1

Speed = Distance/Time. Speed = 24m/87mins = 0.279 m/min. D(6min) = (0.279m/min)*6min = 1.66 m.

Answer 2

Answer:

after 6 minute it will be 1.656 m below the surface.

after 70 minutes the lift goes 9.32 m deep

Step-by-step explanation:

detailed solution given in the attached photo

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