Question

A lift is moving downwards with an acceleration of 1.8m/s. What is the apparent weight realised by a man of mass 50 kg?​

Answer 1

The apparent weight released by the man is 400 N.

Explanation:

Given that,

Acceleration of the lift, $a=1.8\ m/s^2$

Mass of the man, m = 50 kg

We need to find the apparent weight released by a man when the lift us moving down wards. The apparent weight is given by :

W = m(g-a)

g is the acceleration due to gravity

Putting all the values in the above equation such that,

$W = 50\times (9.8-1.8)$

W = 400 N

So, the apparent weight released by the man is 400 N. Hence, this is the required solution.

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