a lift is moving up with an acceleration equal to g/5.The apparent weight of a 60kg man standing in the lift is
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original weight of the man is mg= 60 kg then m= 6
uniform acceleration of the lift is a=g/5=10/2=5
By the formula, apparent weight of the man is m(a+g)= 6(5+10)=15×6= 90 kg
uniform acceleration of the lift is a=g/5=10/2=5
By the formula, apparent weight of the man is m(a+g)= 6(5+10)=15×6= 90 kg
deepak112:
wrong answer
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