A lift is moving upwards with a uniform velocity v in which a block of mass m is lying.the frictional force offered by the block when the friction coefficient is 0.5 is?
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The lift is moving upward with uniform velocity. So it has acceleration=0.
So acceleration relative to block will be g+0=9.8m/s^2.
So frictional force =umg
=0.5×m×9.8
=
4.9m N
So acceleration relative to block will be g+0=9.8m/s^2.
So frictional force =umg
=0.5×m×9.8
=
4.9m N
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