A lift of mass 1000kg is moving with an acceleration of 1 m/s 2 in upward direction. Then find the tension developed in the string connected to the lift.
Answers
Answered by
69
Tension=mg+ma
apply the formulae and find the answer
g=9.8
apply the formulae and find the answer
g=9.8
Answered by
123
hi
here is your answer
............................
T = mg + ma
= 1000 (9.8 + 1)
= 1000 (10.8)
= 10800 N
there fore,
the tension developed in the string = 10800N
................
hope it helps......❤
here is your answer
............................
T = mg + ma
= 1000 (9.8 + 1)
= 1000 (10.8)
= 10800 N
there fore,
the tension developed in the string = 10800N
................
hope it helps......❤
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