Question

A light body a and a heavy body b have equal linear momentum . The kinetic energy of a is

Answer 1

The kinetic enegy of A is greater than that of B  because let the

                                      Momentum of A = p = Momentum of B

        From that if mass of A  =  m₁

                    and  mass of B  = m₂

also given        m₁ < m₂

            Therefore K.E of A =  $\frac{p^{2} }{2m1}$

                        and K.E of B =  $\frac{p^{2} }{2m2}$

                                       From this we can conclude that

                                                        ∵ m₁ < m₂

                                                  K.E of A > KE of B