a light bulb draws 30 mili ampear when the voltage a cross it is to 44 resistance light bulb is
?
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Answer:
1.32 volts is the answer.
Explanation:
Given that current= I = 30 mA= 0.030 amperes and reistance = R = 44 ohms.
.
Since, Ohm's law states that,
V= I.R
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Hence, voltage= V = 0.030 x 44 = 1.32 V.
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