Question

A light bulb draws 300ma when the voltage across it is 240v. The resistance of light bulb is

Answer 1

300ma= 30a= I
V=240v

R=V/I
R=240/30
R=8
I don't know the correct answer
it is just guess

Answer 2

Answer:

The resistance of light bulb is 800 Ohms.

Explanation:

According to ohms law V=IR

$I \propto V \begin{aligned}&I=\frac{1}{R} \times V \\&\mathrm{~V}=\mathrm{I} \mathrm{R}\end{aligned}$

Where V= the potential difference, R= resistance, and I= current flowing.

Ohmic resistance is the resistance that follows ohm's law is called ohmic resistance.

Given

Current $(\mathrm{I})=300 \mathrm{~mA}$=300 x 10⁻³A

Voltage $(\mathrm{V})=240 \mathrm{~V}$

Using Ohm's law, the voltage across the resistor

                                         $(V)=I R$

$\begin{aligned}&\therefore R=\frac{V}{I} \\&\therefore R=\frac{240}{300 \times 10^{-3}}\end{aligned} \\ \therefore \mathrm{R}=\mathbf{8 0 0} Ohms$

The resistance of light bulb is 800 Ohms.